draw an polygon spaced across a 2D path object

[Jayme McColgan]

I'm trying to figure out how to draw the 2d path object and have a triangle inserted evenly spaced along the path.

 

I'm struggling to figure out where the points on the line would be. some direction would be appreciated. thank you 

[Pat Stanford]

vs.PointAlongPolyN

[Marissa Farrell]

The easiest way I've done with with Marionette was to convert a copy of the poly to a NURBS curve and divide the curve into segments to get the points along it.
I'm attaching a file to demonstrate. If you just want the 2D points instead of the 3D points, you'll need to remove the Z value from the resulting list.

Div Curve.vwx

[Jesse Cogswell]

@Jayme McColgan What you are looking for is using vs.GetCustomObjectPath to get a handle to the path object's underlying path, then using vs.PointAlongPoly or vs.PointAlongPolyN as @Pat Stanford suggested to get the X,Y point and vector (if you want to match rotation of the triangles to be tangent to the path).  To space them evenly, I would use vs.CalcPolySegLen to determine the distance between the first and last point (use vs.GetVertNum to get the index of the final point), and divide that by the number of triangles you wish to insert.

[Jayme McColgan]

sorry y'all been awhile. sometimes I gotta do my day job. lol 

 

for those in the future looking for an example here's what I ended up going with. 

 

hPath = vs.GetCustomObjectPath(objectHand)
arrows = int(vs.GetRField(PIO_handle, recname, "arrows"))

amount = arrows + 1
testing = vs.HPerim(hPath) / amount

starting = 0
for i in range(amount - 1):

  starting += testing

  vs.RegularPolygon(0, 0, 30, 3, 1)
  last = vs.LNewObj()

  cur_loc = vs.PointAlongPoly(pathHandle, starting)
  vs.HRotate(last,  0, 0, vs.Vec2Ang(cur_loc[2])-90)
  vs.HMove(last,cur_loc[1][0], cur_loc[1][1])