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Stephan Moenninghoff

Vectorworks, Inc Employee
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Posts posted by Stephan Moenninghoff

  1. 1 minute ago, m.graf said:

    If i have to check my network in a wrapper, i make new "outputs" with named pass nodes (first behind the nodes at the beginning than in the middle ...) then from line to line or node to node i check the Dataflow in the wrapper. (very lengthy 😕

    That's my advice as well. Very good point!

    1 minute ago, m.graf said:

    Number two on my wishlist: wrappers with big Networks (>100 nodes) have to be closed faster! 

    Has this become slower? I had to wait longer than I remembered when I did my last fairly substantial project. Your tiling object must have been horrendous!

  2. 12 minutes ago, Aneesh Carvalho said:

    @Stephan Moenninghoff Yes, I did do that. However, I don't want the symbol to be placed on the line at the symbol's current center point. I'd like to change the symbol's point of inclusion. Let me know if I'm making any sense.

    Thank You

    Sure. Use the move node or feed what comes out of the "Get Point on Poly" (at the p port) into a "get xy" node. perform your additions to the x and y coordinates and feed that back into a point 2 node. That's your new coordinate.

    • Like 1
  3. 26 minutes ago, Aneesh Carvalho said:

    @Pat Stanford and @Stephan Moenninghoff Your suggestions were great. Pat's suggestion did however work for me for what I was trying to achieve. However, I'd like to know if it's possible to change the co-ordinates of a symbol in marionette?

    I used DomC's "Create Symbol" node but the coordinates are not what I want them to be.

    I want to be able to create a symbol and place them evenly on the points of a line you just helped me solve. Your help has been much appreciated.

    Thank You

    The Symbol node takes a point input. Just replace the locus node with the symbol node and reference your symbol.

    • Like 1
  4. @Pat Stanford it may be worth noting that you cannot convert a line to a polygon without adding a third vertex. This is totally logical to old VWX dinosaurs but may not be for newbies. @Aneesh Carvalho other than that, what Pat says. That method will give you the first point on the polygon only so you need to use some more nodes to get the others. Something like this works:

    image.thumb.png.bf3d8cd242f3ac9d71185e20540394a3.png

    Name the polygon (bottom of the Object Info Palette) and use that as a criteria in the "Objs by Crit" node to identify the object that you want the Marionette to act on. Note that the polygon has three vertices, so it looks like a line but is, in fact, a polygon.

    • Like 2
  5. That worked.

    Create a drape surface. U and V iteration = 100. 

    Name it "test2".

    Run the Marionette.

    Adjust level of embedding by changing the insertion point of the symbol and the rotation values in the Marionette.

    Ungroup.

    Reference a different symbol and repeat.

    Delete the symbol instances that are outside the icing and those that collide with others. Max. 10 minutes clean-up work.

    You could try and expand the Marionette to go looking for symbols that are placed too closely to others but it's hardly worth the effort, I don't think.

    Sprinkle.thumb.png.316d518846a40578b183d044d01c2324.png

    Sprinkle v 2.0.vwx

    • Like 3
  6. FWIW, the way I went about placing the sprinkles via Marionette was to generate curves from the model and getting the points on each curve by subdivision. Each sprinkle-symbol is then placed on one of those points and rotated randomly. That is why they get embedded. If there was a way to generate random points on each surface of the frosting model and getting the normal's orientation at that point, the sprinkles could be placed perpendicular to the surface and then be rotated randomly. Unfortunately I don't know of a way to do that with Marionette.

  7. 2 hours ago, Pat Stanford said:

    Another possibility would be to make the frosting as a Digital Terrain Model. Then you could use the Send to Surface command to put the sprinkles on the frosting.

    I tried that.  The frosting has overhanging cliffs, depending on the degree of twisting and the depth of the ridges. I don't think the DTM is meant to handle such conditions. 

    image.thumb.png.bd158d707fb9d0224fabf2b6ea578806.png

  8. 53 minutes ago, Bruce Kieffer said:

     

    Certainly the easiest, and probably super expensive.

    Ingredients for a single cupcake shouldn't be excessive. And IIRC Vectorworks now has photogrammetric visual scanning. I haven't tried it but it's not a bad idea!

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