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On a cabinet I can put 1:4 input to manage 1/4 of total space

The results Is 1:4:#:#

So if I try to write 1:4:#:1/4 to have 1/4 above, 1/4 top and the rest in the middle it works, but the impute is modified to 1:4:#:1 and it generate 3 spaces (not 4)

If I try to write 1:4:#:#:1/4 there is no way to have 1/4 above, 1/4 top and other 2 space in the middle

You cannot use a hash placeholder when you use proportional division. It is not logical. Which proportion of the total height should the hash occupy? You have ratios of divisions so if you have a total of four boxes, you can input 1:2:2.4:3 but you cannot use a hash.

You can use a hash if you use percentages: 30%;30%;10%;# will work for example.

17 minutes ago, Stephan Moenninghoff said:

30%;30%;10%;# will work for example.

Yeah that's exactly what I need, thank you!

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