Get data from a Worksheet with Python script?

[Vsevolod 0]

I've been trying to get data from a worksheet by Python script. Here is the basic code:

 

def FindTable():
    hLayer = vs.GetParent( vs.FObject() )
    vs.EnableDrawingWorksheetPalette(True, None)

    while hLayer != None:
        h = vs.FInLayer( hLayer )
        while h != None:
            # worksheet?
            if vs.GetTypeN(h) == 56:
                rows, cols = vs.GetWSRowColumnCount(h)
                cellnum = vs.GetCellStr(h,1,1)
                vs.AlrtDialog( vs.Concat('Cell 1 ',cellnum,' Name: ',vs.GetName(h),' visible: ',vs.AreWorksheetGridLinesVisible(h),' rows=', rows, ' cols=', cols) )
            
            h = vs.NextObj( h )
        hLayer = vs.NextLayer( hLayer )

    return 0

 

It doesn't work and returns 0 rows and columns. I guess "Worksheet container" type is not good and these APIs  don't work but the cycle returns only handle with type 56 even without any 'if' condition.

Maybe "Worksheet" type is what I'm looking for?  types and IDs  But how can I obtain it?

[MullinRJ 211]

 

Vsevolod,

The object on the drawing layer is a WORKSHEET IMAGE (type 56). You need a handle to the WORKSHEET (type 18), which is a resource.

 

Add this line:

hWS = vs.GetWSFromImage(h)        # handle to WS resource

and use hWS in your subsequent calls. 

def FindTable():
	hLayer = vs.GetParent( vs.FObject() )
	vs.EnableDrawingWorksheetPalette(True, None)
	while hLayer != None:
		h = vs.FInLayer( hLayer )
		while h != None:
			# worksheet?
			if vs.GetTypeN(h) == 56:
				hWS = vs.GetWSFromImage(h)		# handle to WS resource
				rows, cols = vs.GetWSRowColumnCount(hWS)
				cellnum = vs.GetCellStr(hWS,1,1)
				vs.AlrtDialog( vs.Concat('Cell 1 ',cellnum,' Name: ',vs.GetName(h),' visible: ',vs.AreWorksheetGridLinesVisible(hWS),' rows=', rows, ' cols=', cols) )
            
			h = vs.NextObj( h )
		hLayer = vs.NextLayer( hLayer )
	return 0

 

Raymond

Edited January 19, 2017 by MullinRJ

[Vsevolod 0]

Yes, I've checked your code and it runs exactly as you said and what I'm searching for!

Thanks, Raymond!

[MullinRJ 211]

You're welcome. I missed a handle...   vs.GetName(h) returns "none", if you change it to vs.GetName(hWS) you'll get "Worksheet-1" or whatever you named your worksheet.

 

Welcome to the VW programming forum.

 

Raymond