Vsevolod Posted January 19, 2017 Share Posted January 19, 2017 I've been trying to get data from a worksheet by Python script. Here is the basic code: def FindTable(): hLayer = vs.GetParent( vs.FObject() ) vs.EnableDrawingWorksheetPalette(True, None) while hLayer != None: h = vs.FInLayer( hLayer ) while h != None: # worksheet? if vs.GetTypeN(h) == 56: rows, cols = vs.GetWSRowColumnCount(h) cellnum = vs.GetCellStr(h,1,1) vs.AlrtDialog( vs.Concat('Cell 1 ',cellnum,' Name: ',vs.GetName(h),' visible: ',vs.AreWorksheetGridLinesVisible(h),' rows=', rows, ' cols=', cols) ) h = vs.NextObj( h ) hLayer = vs.NextLayer( hLayer ) return 0 It doesn't work and returns 0 rows and columns. I guess "Worksheet container" type is not good and these APIs don't work but the cycle returns only handle with type 56 even without any 'if' condition. Maybe "Worksheet" type is what I'm looking for? types and IDs But how can I obtain it? Quote Link to comment
MullinRJ Posted January 19, 2017 Share Posted January 19, 2017 (edited) Vsevolod, The object on the drawing layer is a WORKSHEET IMAGE (type 56). You need a handle to the WORKSHEET (type 18), which is a resource. Add this line: hWS = vs.GetWSFromImage(h) # handle to WS resource and use hWS in your subsequent calls. def FindTable(): hLayer = vs.GetParent( vs.FObject() ) vs.EnableDrawingWorksheetPalette(True, None) while hLayer != None: h = vs.FInLayer( hLayer ) while h != None: # worksheet? if vs.GetTypeN(h) == 56: hWS = vs.GetWSFromImage(h) # handle to WS resource rows, cols = vs.GetWSRowColumnCount(hWS) cellnum = vs.GetCellStr(hWS,1,1) vs.AlrtDialog( vs.Concat('Cell 1 ',cellnum,' Name: ',vs.GetName(h),' visible: ',vs.AreWorksheetGridLinesVisible(hWS),' rows=', rows, ' cols=', cols) ) h = vs.NextObj( h ) hLayer = vs.NextLayer( hLayer ) return 0 Raymond Edited January 19, 2017 by MullinRJ 1 Quote Link to comment
Vsevolod Posted January 19, 2017 Author Share Posted January 19, 2017 Yes, I've checked your code and it runs exactly as you said and what I'm searching for! Thanks, Raymond! Quote Link to comment
MullinRJ Posted January 19, 2017 Share Posted January 19, 2017 You're welcome. I missed a handle... vs.GetName(h) returns "none", if you change it to vs.GetName(hWS) you'll get "Worksheet-1" or whatever you named your worksheet. Welcome to the VW programming forum. Raymond 1 Quote Link to comment
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.