Check if Object is a Container

[Patrick Winkler]

Hello,

I need to check if a object conatins other objects.

Therefore I wrote this function:

def isContainerObj (obj):
   return vs.FInGroup(obj) != vs.Handle (0) 

It works but vs.FInGroup will return a error Message to the console when the objects is no container.

Has someone a more elegant solution for this.

thanks

Edited April 15, 2016 by Patrick Winkler

[Marissa Farrell]

What if you check the type of the object you're querying to see if it's a group or a symbol or another object type that could qualify as a container? That should let you know if it will have any "children".

Still a little clunky, but I'm sure there aren't many other object types that would qualify as a container.

[Marissa Farrell]

In addition, if it IS a group/symbol/container object, you may also want to call GetParent on it to see if it's a child of ANOTHER group/symbol/container. (If it returns a Layer, then you're at the outermost container object)

Edited April 15, 2016 by MarissaF

[JBenghiat]

You should be able to use the error to your advantage:

def isContainerObj (obj):
   try:
	h = vs.FInGroup(obj)
   except:
	return false
   else:
	return true

-Josh

[Patrick Winkler]

thanks,

it seems to be no real exception, the error get's printed to the console anyway and the Result is always True.

[Patrick Winkler]

I'm not sure about it but checking the type for vs.HandleContainer () should work accurate.

def isContainerObj (h):
t = type (h)

print (t)

return not type (h) == type (vs.Handle(0)) 



h = vs.FSActLayer ()
print ( isContainerObj (h) )

Maybe some one can confirm this.