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worksheet operation =round?


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Kristen,

I just tried it in VW8.5.2 and ROUND only accepts 1 argument, but the documentation shows that it accepts 2. Probably an error in the documentation, or just wishful thinking.

Try: =Round(123.456789*10^3)/10^3

to get 3 decimals of precision, where 10^3 is 10 raised to the 3rd power, or 1000. Change the 3 to whatever precision you desire.

This should evaluate as:

Round(123456.789)/1000 -> 123457/1000 -> 123.457

HTH,

Raymond

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