Getting aspect ratio of a RenderWorks texture image

[Jayme McColgan]

I'm really struggling to get the aspect ratio of a RenderWorks texture image. any pointers would be appreciated

 

ive tried these plus a few others with no real luck. 

vs.GetTexBFeatureStart(textureBitmap)

vs.GetTexBFeatureEnd(textureBitmap)

vs.GetTexBitFeatureSize(textureBitmap)

 

[Pat Stanford]

I don't see a procedure/function to get what you want.

 

Can't you just get the Begin and End X and Y values (Xb, Xe, Yb, Ye), subtract them to get the pixel size (Xe-Xb, Ye-Yb) and then divide them to get the aspect ratio? 

[Dave Donley]

You will want to do get shader record from the texture resourec, then get texture bitmap from shader record, then get texture bitmap paint node.  Then get object variable with these selectors:
 

const short ovPaintWidthPixels = 530; // Sint32 - Public for VS

const short ovPaintHeightPixels = 531; // Sint32 - Public for VS

 

HTH

[Jayme McColgan]

@Dave Donley

 

I tried this code with no luck. The first 3 all return handles, but when I try to get the paint node, it returns "None". 

 

Also, the wiki says that vs.GetTexBitPaintNode(textureBitmap) is obsolete. Am I using the right function? 

 

ledtext2 = vs.GetObject(ledimage)
shrec = vs.GetShaderRecord(ledtext2, 1)
texbit = vs.GetTextureBitmap(shrec)
paintnode =vs.GetTexBitPaintNode(texbit)
texwidth = vs.GetObjectVariableInt(paintnode, 530)

vs.Message(f"{ledtext2} / {shrec} / {texbit} / {paintnode} / {texwidth}")

 

[Dave Donley]

Try this one with get object variable handle on the shader record handle:
 

const short ovShaderRecordImageDefNode = 550; // MCObjectHandle (image node) - Get only

const short ovShaderRecordGrayscaleImageDefNode = 551; // MCObjectHandle (8-bit image node) - Get only

[Jayme McColgan]

2 hours ago, Pat Stanford said:

I don't see a procedure/function to get what you want.

 

Can't you just get the Begin and End X and Y values (Xb, Xe, Yb, Ye), subtract them to get the pixel size (Xe-Xb, Ye-Yb) and then divide them to get the aspect ratio? 

 

hey Pat! been a while. 

 

I'm going to explore this, but sometimes these textures are on a surface that is faceted or curved. just getting the distance between X1,Y1 and X2,Y2 would always work but its a good direction to look. 

[Jayme McColgan]

@Dave Donley

 

SUCCESS! The code below got me the pixel dims of the texture. Thank you, sir. 

ledtext2 =  vs.GetObject(ledimage)
shrec = vs.GetShaderRecord(ledtext2, 1)
varhan = vs.GetObjectVariableHandle(shrec, 550)
texwid = vs.GetObjectVariableLongInt(varhan, 534)
texhei = vs.GetObjectVariableLongInt(varhan, 535)

 

 

Can I also get some help with understanding what the units that offsetX:1, offsetY:2 for vs.SetTexMapRealN() use? It seems like it's millimeters, no matter what dim mode I have the document in. Is that true? I'd like to use a dimension field in the PIO to set this, but I'm not sure what units to convert it to. 

 

vs.SetTexMapRealN(last, 3, 0, 1, xoff)
vs.SetTexMapRealN(last, 3, 0, 2, yoff)

 

[Dave Donley]

Yes I would expect millimeters, those are the internal units Vectorworks uses for coords and dims.

[Jayme McColgan]

@Dave Donley currently I'm using vs.ValidNumStr(vs.GetRField(PIO_handle, recname, "X Offset"))[1] to get the dimension from the field. Is there a function to then turn that into millimeters so i can do the image offset for the texture, since that only wants mm? 

[Pat Stanford]

Returned number * DPI returned by GetUnits * 25.4 (mm/inch)??

 

PROCEDURE GetUnits( VAR fraction : LONGINT; VAR display : LONGINT; VAR format : INTEGER; VAR upi : REAL; VAR name : STRING; VAR squareName : STRING);